[tex]\frac { 3 } { 2 - \sqrt { 3 } } = [/tex]
rasionalkan pemyebut bentuk akar berikut
Jawab:
Penjelasan dengan langkah-langkah:
[tex]\frac{3(2+\sqrt{3}) }{(2-\sqrt{3})(2+\sqrt{3}) }[/tex]
(a−b)(a+b)= a²-b²
[tex]\frac{3(2+\sqrt{3}) }{2^2-(\sqrt{3})^2 }[/tex]
6+3√3
[tex]\frac{3}{2 - \sqrt{3}} = \frac{3}{2 - \sqrt{3}} \times \frac{2 + \sqrt{3}}{2 + \sqrt{3}} = \frac{(3)(2 + \sqrt{3})}{(2 - \sqrt{3})(2 + \sqrt{3})} [/tex]
[tex]= \frac{6 + 3 \sqrt{3}}{4 + 2 \sqrt{3} - 2 \sqrt{3} - \sqrt{9}} [/tex]
[tex]= \frac{6 + 3 \sqrt{3}}{4 - \sqrt{9}} = \frac{6 + 3 \sqrt{3}}{4 - 3} = \frac{6 + 3 \sqrt{3}}{1} = 6 + 3 \sqrt{3} [/tex]
[answer.2.content]
